In \(\triangle ABC\), \(\angle A = 80^\circ\). The bisectors of the exterior angles at B and C meet at O. Find \(\angle BOC\).
A. \(130^\circ\)
B. \(50^\circ\)
C. \(40^\circ\)
D. \(100^\circ\)
A. \(130^\circ\)
B. \(50^\circ\)
C. \(40^\circ\)
D. \(100^\circ\)
Best answer
Answer: B. \(50^\circ\)
Answer: (B) \(50^\circ\)
For the excentre formed by the external bisectors at B and C: \(\angle BOC = 90^\circ - \frac{\angle A}{2} = 90^\circ - 40^\circ = 50^\circ\). (\(130^\circ = 90^\circ + 40^\circ\) would be the answer for the internal bisectors.)
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