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Answer: B. \(50^\circ\)

Answer: (B) \(50^\circ\)

For the excentre formed by the external bisectors at B and C: \(\angle BOC = 90^\circ - \frac{\angle A}{2} = 90^\circ - 40^\circ = 50^\circ\). (\(130^\circ = 90^\circ + 40^\circ\) would be the answer for the internal bisectors.)

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report
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