In triangle ABC, I is the incentre and ∠A = 70°. Find ∠BIC.
A. 110°
B. 135°
C. 140°
D. 125°
A. 110°
B. 135°
C. 140°
D. 125°
Best answer
Answer: D. 125°
Answer: (D) 125°
\(\angle BIC = 90^\circ + \frac{\angle A}{2} = 90^\circ + 35^\circ = 125^\circ\).
Reason: \(\angle IBC + \angle ICB = \frac{1}{2}(180^\circ - 70^\circ) = 55^\circ\), so \(\angle BIC = 180^\circ - 55^\circ = 125^\circ\). (140° is the angle at the circumcentre.)
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