Find \(\dfrac{d^2y}{dx^2}\), if \(y = x^3 + 7x^2 - 2x - 9\).
Q.10 Find \(\dfrac{d^2y}{dx^2}\), if \(y = x^3 + 7x^2 - 2x - 9\).
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Answer: \(\dfrac{d^2y}{dx^2} = 6x + 14\)
\(\dfrac{dy}{dx} = 3x^2 + 14x - 2\), and differentiating again, \(\dfrac{d^2y}{dx^2} = 6x + 14\).
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· 28 Oct 2026
AI-verified · Oct 2026
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