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Answer: B. benzenol

Answer: (b) benzenol

The O–CH3 bond is cleaved by HI. Because the O–C(aryl) bond has partial double-bond character, iodide attacks the methyl carbon, giving phenol (benzenol) and methyl iodide:

C6H5–O–CH3 + HI \(\xrightarrow{398\ \text{K}}\) C6H5OH + CH3I

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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