Write a note on Kolbe reaction.
Q.11 Write a note on Kolbe reaction.
Q.11 Write a note on Kolbe reaction.
Best answer
Answer: In the Kolbe reaction, sodium phenoxide is heated with carbon dioxide at about 398 K under 4–7 atm pressure. The phenoxide ion, being strongly activated, undergoes electrophilic substitution by the weak electrophile CO2 at the ortho position, forming sodium salicylate; acidification gives salicylic acid (o-hydroxybenzoic acid).
C6H5ONa + CO2 \(\xrightarrow{398\ \text{K},\ 4\text{–}7\ \text{atm}}\) o-HO–C6H4–COONa (sodium salicylate)
o-HO–C6H4–COONa + HCl → o-HO–C6H4–COOH (salicylic acid) + NaCl
Salicylic acid is used to make aspirin.
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