In first order reaction 60% of reactant decomposes in 40 min. Calculate the rate constant of the reaction.
Q.13 In first order reaction 60% of reactant decomposes in 40 min. Calculate the rate constant of the reaction.
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Answer: k = 0.0229 min–1 (3.82 × 10–4 s–1)
If \([A]_0 = 100\), after 40 min \([A]_t = 100 - 60 = 40\).
\(k = \dfrac{2.303}{t}\log_{10}\dfrac{[A]_0}{[A]_t} = \dfrac{2.303}{40}\log_{10}\dfrac{100}{40} = \dfrac{2.303}{40}\times\log_{10}2.5\)
\(= \dfrac{2.303 \times 0.3979}{40} = \dfrac{0.9164}{40} = 0.0229\ \text{min}^{-1}\)
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· 28 Oct 2026
AI-verified · Oct 2026
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