Skip to content
doubtly

1 answer

Best answer

Answer:

(a) Dehydration of ethanol with conc. H2SO4 at 413 K:

2 C2H5OH \(\xrightarrow{\text{conc. H}_2\text{SO}_4,\ 413\ \text{K}}\) C2H5–O–C2H5 + H2O

(b) Oxidation of phenol with sodium dichromate and sulphuric acid (chromic acid):

C6H5OH \(\xrightarrow{\text{Na}_2\text{Cr}_2\text{O}_7/\text{H}_2\text{SO}_4}\) O=C6H4=O (p-benzoquinone) [a six-membered ring with C=O groups at positions 1 and 4 and two C=C bonds]

(c) Acetylation of salicylic acid with acetic anhydride (acid catalyst):

o-HO–C6H4–COOH + (CH3CO)2O \(\xrightarrow{\text{H}^+}\) o-CH3COO–C6H4–COOH (aspirin, acetylsalicylic acid) + CH3COOH

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.