The displacement of a particle at time \(t\) is given by \(S = 3t^2 + 4t + 1\). Find its velocity at time \(t\).
Q.2 (iii) The displacement of a particle at time \(t\) is given by \(S = 3t^2 + 4t + 1\). Find its velocity at time \(t\).
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Answer: \(v = 6t + 4\)
Velocity \(v = \frac{dS}{dt} = \frac{d}{dt}(3t^2 + 4t + 1) = 6t + 4\).
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· 28 Oct 2026
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