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Answer: C. \(\Lambda = \dfrac{1000k}{c}\)

Answer: (c) \(\Lambda = \dfrac{1000k}{c}\)

Molar conductivity \(\Lambda = \dfrac{1000\,k}{c}\) where \(k\) is conductivity in \(\Omega^{-1}\) cm\(^{-1}\) and \(c\) is concentration in mol L\(^{-1}\); \(\Lambda\) is then in \(\Omega^{-1}\) cm\(^2\) mol\(^{-1}\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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