Q.1 (v) Correct statement about electrolysis of aqueous NaCl is _____.
A. H2 gas liberated at cathode
B. Cl2 gas liberated at cathode
C. H2 gas liberated at anode
D. O2 gas liberated at anode
Best answer
Answer: A. H2 gas liberated at cathode
Answer: (a) H2 gas liberated at cathode
At the cathode water is reduced more easily than Na+: 2H2O + 2e– → H2 + 2OH–. At the anode Cl– is oxidised (because of overpotential for O2): 2Cl– → Cl2 + 2e–. So H2 is liberated at the cathode and Cl2 at the anode.
Log in or create a free account to answer this question.
