Answer:
(a) H2–O2 fuel cell with porous carbon electrodes and aqueous KOH (or NaOH) electrolyte:
Anode (oxidation): 2H2(g) + 4OH–(aq) → 4H2O(l) + 4e–
Cathode (reduction): O2(g) + 2H2O(l) + 4e– → 4OH–(aq)
Overall: 2H2(g) + O2(g) → 2H2O(l)
(b) Application (any one): It helps predict whether a redox reaction is spontaneous: a metal with lower (more negative) standard reduction potential displaces a metal with higher reduction potential from its salt solution, e.g. Zn displaces Cu from CuSO4. (It also compares the strengths of oxidising/reducing agents and helps calculate the standard emf of a cell, \(E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}}\).)