Asked in: July 2024 board paperFind the value of the following determinant : \(\begin{vmatrix} 5 & -2 \\ -3 & 1 \end{vmatrix}\).

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: −1

\(\begin{vmatrix} a & b \\ c & d \end{vmatrix} = ad - bc\)

\(\therefore \begin{vmatrix} 5 & -2 \\ -3 & 1 \end{vmatrix} = (5)(1) - (-2)(-3) = 5 - 6 = -1\)

(The July 2025 paper asked the same skill with \(\begin{vmatrix} 5 & 3 \\ -7 & -4 \end{vmatrix} = -20 - (-21) = 1\).)

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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