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Answer: \(x + y = 5\) and \(x - y = 1\)

\(101x + 99y = 501\) …(I)
\(99x + 101y = 499\) …(II)

Adding (I) and (II): \(200x + 200y = 1000\)

\(\therefore x + y = 5\) …(III)

Subtracting (II) from (I): \(2x - 2y = 2\)

\(\therefore x - y = 1\) …(IV)

(If asked further, adding (III) and (IV) gives \(2x = 6\), so \(x = 3\) and \(y = 2\).)

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report
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