Asked in: July 2024 and March 2025 board papers; March 2024 asked “find \(x\) when \(y = 1\)” for the same equationComplete the following table for drawing the graph of the equation : \(x + 2y = 4\)\(x\)−20\(y\)21\((x, y)\)(0, 2)

Asked in: July 2024 and March 2025 board papers; March 2024 asked “find \(x\) when \(y = 1\)” for the same equation

Complete the following table for drawing the graph of the equation : \(x + 2y = 4\)

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: \(y = 3\) when \(x = -2\); \(x = 2\) when \(y = 1\); points \((-2, 3)\), \((0, 2)\), \((2, 1)\)

When \(x = -2\): \(-2 + 2y = 4 \Rightarrow 2y = 6 \Rightarrow y = 3\). Point \((-2, 3)\).

When \(y = 1\): \(x + 2(1) = 4 \Rightarrow x = 2\). Point \((2, 1)\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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