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Topic: Refraction through a prism· Optics

The angle of incidence for a ray of light at a refracting surface of a prism is 45^°. The angle of prism is 60^°. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism…

The angle of incidence for a ray of light at a refracting surface of a prism is \(45^\circ\). The angle of prism is \(60^\circ\). If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are :

1. \(45^\circ;\ \frac{1}{\sqrt{2}}\)

2. \(30^\circ;\ \sqrt{2}\)

3. \(45^\circ;\ \sqrt{2}\)

4. \(30^\circ;\ \frac{1}{\sqrt{2}}\)

1 answer

Best answer

Answer: 2. \(30^\circ;\ \sqrt{2}\)

Key idea: at minimum deviation the ray passes symmetrically, so \(r_1=r_2=A/2\) and \(i=\dfrac{A+\delta_m}{2}\).

  1. \(r=30^\circ\); \(\mu=\dfrac{\sin45^\circ}{\sin30^\circ}=\sqrt2\).
  2. \(\delta_m=2i-A=90^\circ-60^\circ=30^\circ\).
Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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