1. 2 mC 2. 5 mC 3. 7 μ C 4. 8 mC

Answer: 1. 2 mC Torque on a dipole: τ=pEsinθ , with p=q l . 4=q(0.02)(2×10⁵)sin30^°=q×2000 q=4/2000=2×10⁻³ C =2 mC. Option (1).

An electric dipole is placed at an angle of 30° with an electric field intensity 2×10^5 N/C. It experiences a torque equal to 4 N m. The charge on the dipole, if the dipole length is 2 cm, is

1. 2 mC

2. 5 mC

3. 7 $\mu$C

4. 8 mC

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 2 Practice test neet Save WhatsApp Report

Best answer

Answer: 1. 2 mC

Torque on a dipole: $\tau=pE\sin\theta$, with $p=q\,l$.

$$4=q(0.02)(2\times10^5)\sin30^\circ=q\times2000$$

$q=\dfrac{4}{2000}=2\times10^{-3}$ C $=2$ mC. Option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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