An electric dipole is placed at an angle of 30^° with an electric field of intensity 2×10^5 N C^-1. It experiences a torque equal to 4 N m. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

1. 2 mC

2. 8 mC

3. 6 mC

4. 4 mC

Doubtly Asked 30 Oct 2026 NEET UG 2023 Practice test neet Save WhatsApp Report

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Answer: 1. 2 mC

Torque on a dipole: \(\tau = pE\sin\theta\), with \(p=q\cdot l\).

\(4 = q(0.02)(2\times10^{5})\sin30^\circ = q\times 2000\)

\(q = 2\times10^{-3}\) C = 2 mC.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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