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Topic: Electric dipole, field due to dipole, torque in uniform field· Electrostatics

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector P of magnitude, 4×10^-6…

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : The potential (\(V\)) at any axial point, at 2 m distance(\(r\)) from the centre of the dipole of dipole moment vector \(\vec{P}\) of magnitude, \(4\times10^{-6}\) C m, is \(\pm9\times10^3\) V.

(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)

Reason R : \(V=\pm\frac{2P}{4\pi\epsilon_0 r^2}\), where \(r\) is the distance of any axial point, situated at 2 m from the centre of the dipole.

In the light of the above statements, choose the correct answer from the options given below:

1. A is false but R is true.

2. Both A and R are true and R is the correct explanation of A.

3. Both A and R are true and R is NOT the correct explanation of A.

4. A is true but R is false.

1 answer

Best answer

Answer: 4. A is true but R is false.

Key idea: Potential of a dipole at an axial point: \(V=\pm\frac{p}{4\pi\epsilon_0r^2}\).

Assertion: \(V=\frac{9\times10^9\times4\times10^{-6}}{2^2}=9\times10^3\) V, so A is true.

Reason: it gives the formula with an extra factor 2 (\(\frac{2p}{\ldots}\)), which is the formula for the axial electric field, not the potential. So R is false.

A is true, R is false: option 4.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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