Topic: Einstein's photoelectric equation, particle nature of light· Dual Nature of Matter and Radiation

Photons with energy 5 eV are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of…

Photons with energy 5 eV are incident on a cathode \(C\) in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on \(C\), no photoelectrons will reach the anode \(A\), if the stopping potential of \(A\) relative to \(C\) is

1. +4 V

2. -1 V

3. -3 V

4. +3 V

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 2 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 3. -3 V

Einstein's equation: \(K_{max}=h\nu-\phi\).

5 eV photon, \(K_{max}=2\) eV, so \(\phi=3\) eV.
6 eV photon: \(K_{max}=6-3=3\) eV.

To stop all electrons the anode must be at \(-3\) V relative to the cathode (retarding potential). Option (3). A positive potential would attract electrons.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?

Photons with energy 5 eV are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of…

1 answer

Your answer