1. 10¹⁸ 2. 10¹⁷ 3. 10¹⁶ 4. 10¹⁵

Answer: 3. 10¹⁶ Key idea: number of photons per second N=P/hc/λ=Pλ/hc . N=dfrac3.3×10⁻³×600×10⁻⁹6.6×10⁻³⁴×3×10⁸=dfrac1.98×10⁻⁹1.98×10⁻²⁵=10¹⁶ per second. Option 3.

Topic: Einstein's photoelectric equation, particle nature of light· Dual Nature of Matter and Radiation

The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3×10^-3 watt will be : (h = 6.6×10^-34 Js)

1. \(10^{18}\)

2. \(10^{17}\)

3. \(10^{16}\)

4. \(10^{15}\)

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Answer: 3. \(10^{16}\)

Key idea: number of photons per second \(N=\dfrac{P}{hc/\lambda}=\dfrac{P\lambda}{hc}\).

\(N=\dfrac{3.3\times10^{-3}\times600\times10^{-9}}{6.6\times10^{-34}\times3\times10^8}=\dfrac{1.98\times10^{-9}}{1.98\times10^{-25}}=10^{16}\) per second. Option 3.

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The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3×10^-3 watt will be : (h = 6.6×10^-34 Js)

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