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Topic: Einstein's photoelectric equation, particle nature of light· Dual Nature of Matter and Radiation

When two monochromatic lights of frequency, and /2 are incident on a photoelectric metal, their stopping potential becomes V_s/2 and V_s respectively. The threshold frequency for this metal is :

1. \(\frac{3}{2}\nu\)

2. \(2\nu\)

3. \(3\nu\)

4. \(\frac{2}{3}\nu\)

1 answer

Best answer

Answer: 1. \(\frac{3}{2}\nu\)

Einstein's equation: \(eV_s=h(\nu-\nu_0)\), so stopping potential is proportional to \((\nu-\nu_0)\).

Taking the ratio of the two cases: \(\dfrac{V_s/2}{V_s}=\dfrac{\nu-\nu_0}{\nu/2-\nu_0}=\dfrac12\)

\(\nu/2-\nu_0=2\nu-2\nu_0\Rightarrow \nu_0=\dfrac{3}{2}\nu\)

So option (1) matches the official key.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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