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Answer: 2. accepts \(OH^-\) from water releasing proton

Key idea: boric acid is a Lewis acid, not a proton donor.

Boron in \(\mathrm{B(OH)_3}\) has an empty p-orbital. It accepts \(OH^-\) from water and a proton is released:

$$\mathrm{B(OH)_3+2H_2O\rightarrow [B(OH)_4]^-+H_3O^+}$$

So it accepts \(OH^-\) from water, releasing a proton. It does not itself give a proton (option 1) and has no ionisable \(H^+\) of its own in this sense (option 4).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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