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Answer: 1. \(K_3[AlF_6]\)

Key idea: \(AlF_3\) is covalent and insoluble; extra \(F^-\) from KF forms a soluble complex.

$$\mathrm{AlF_3+3KF\rightarrow K_3[AlF_6]}$$

The stable hexafluoroaluminate ion \([AlF_6]^{3-}\) is soluble. Hydride-containing species are not formed because no hydride source is present.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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