1. trigonal bipyramidal, sp³d 2. planar triangle, sp³d³ 3. square planar, sp³d² 4. octahedral, sp³d²

Answer: 3. square planar, sp³d² Key idea: Xe in XeF₄ has 4 bond pairs and 2 lone pairs. Steric number 6 gives sp³d² hybridisation and an octahedral electron arrangement. The two lone pairs sit opposite each other, so the molecule is square planar.

Topic: VSEPR theory and shapes of molecules· Chemical Bonding and Molecular Structure

The correct geometry and hybridization for XeF_4 are

1. trigonal bipyramidal, \(sp^3d\)

2. planar triangle, \(sp^3d^3\)

3. square planar, \(sp^3d^2\)

4. octahedral, \(sp^3d^2\)

Doubtly Asked 30 Oct 2026 NEET UG 2016 Phase 2 neet Save WhatsApp Report

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Answer: 3. square planar, \(sp^3d^2\)

Key idea: Xe in \(XeF_4\) has 4 bond pairs and 2 lone pairs.

Steric number 6 gives \(sp^3d^2\) hybridisation and an octahedral electron arrangement. The two lone pairs sit opposite each other, so the molecule is square planar.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The correct geometry and hybridization for XeF_4 are

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