Skip to content
doubtly

1 answer

Best answer

Answer: 1. \(XeF_2\)

Key idea: compare the number of lone pairs on the central atom and their arrangement.

  • \(\mathrm{XeF_2}\): 3 lone pairs on Xe (trigonal bipyramidal electron geometry, all three in the equatorial plane at 120 degrees).
  • \(\mathrm{ClF_3}\): 2 lone pairs.
  • \(\mathrm{IF_5}\): 1 lone pair.
  • \(\mathrm{SF_4}\): 1 lone pair.

With three lone pairs, \(\mathrm{XeF_2}\) has the most lone pair-lone pair repulsions (three pair interactions versus one in \(\mathrm{ClF_3}\) and none in the other two). So the answer is option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.