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Topic: VSEPR theory and shapes of molecules· Chemical Bonding and Molecular Structure

Match List I with List II.List I (Compound): A. NH_3 B. BrF_5 C. XeF_4 D. SF_6List II (Shape/geometry): I. Trigonal Pyramidal II. Square Planar III. Octahedral IV. Square PyramidalChoose the correct answer from the options given below:

1. A-II, B-III, C-IV, D-I

2. A-I, B-IV, C-II, D-III

3. A-II, B-IV, C-III, D-I

4. A-III, B-IV, C-I, D-II

1 answer

Best answer

Answer: 2. A-I, B-IV, C-II, D-III

Key idea: use VSEPR to get the shape of each molecule.

  • \(\mathrm{NH_3}\): 3 bond pairs + 1 lone pair gives trigonal pyramidal (I).
  • \(\mathrm{BrF_5}\): 5 bond pairs + 1 lone pair gives square pyramidal (IV).
  • \(\mathrm{XeF_4}\): 4 bond pairs + 2 lone pairs gives square planar (II).
  • \(\mathrm{SF_6}\): 6 bond pairs gives octahedral (III).

So A-I, B-IV, C-II, D-III: option 2.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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