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Answer: 4. III only

Key idea: keto-enol tautomerism needs an alpha-H, and the enol must be able to form (a double bond at a bridgehead is not allowed, by Bredt's rule).

  • I: the C=O is on the one-carbon bridge; its alpha carbons are bridgeheads, so the enol would have a bridgehead double bond. Not possible.
  • II: one alpha carbon has two Ph (no H); the other is a bridgehead. Not possible.
  • III: has an alpha \(CH_2\) away from the bridgehead, so enolisation is possible.

Only III shows tautomerism.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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