The compound which shows metamerism is :
1. \(C_5H_{12}\)
2. \(C_3H_8O\)
3. \(C_3H_6O\)
4. \(C_4H_{10}O\)
1. \(C_5H_{12}\)
2. \(C_3H_8O\)
3. \(C_3H_6O\)
4. \(C_4H_{10}O\)
Best answer
Answer: 4. \(C_4H_{10}O\)
Key idea: metamerism occurs between compounds with the same functional group (usually ethers, ketones, secondary amines) but different alkyl groups on either side of the functional group.
\(\mathrm{C_4H_{10}O}\) has ethers such as \(\mathrm{CH_3OCH_2CH_2CH_3}\) and \(\mathrm{C_2H_5OC_2H_5}\): same group, different alkyl distribution, so metamers.
\(\mathrm{C_5H_{12}}\) shows chain isomerism only; \(\mathrm{C_3H_8O}\) has only one possible ether (\(\mathrm{CH_3OC_2H_5}\)); \(\mathrm{C_3H_6O}\) has no pair of ketone metamers.
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