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Answer: 4. 1,2-Dimethylcyclohexane

Key idea: cis-trans isomerism needs a double bond with different groups on each carbon, or a ring with two substituents on different ring carbons.

  • Pent-1-ene: terminal \(\mathrm{=CH_2}\), no.
  • 2-Methylhex-2-ene: one alkene carbon has two \(\mathrm{CH_3}\), no.
  • 1,1-Dimethylcyclopropane: both groups on the same carbon, no.
  • 1,2-Dimethylcyclohexane: methyls can be on the same side (cis) or opposite sides (trans), yes.

Option (4).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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