1. ClF₃ 2. NCl₃ 3. BCl₃ 4. PH₃

Answer: 3. BCl₃ Key idea: 120^° belongs to a trigonal planar molecule with no lone pair on the central atom. BCl₃ : B has 3 bond pairs, sp² , planar, 120^° . NCl₃ and PH₃ are pyramidal (one lone pair, angles near 107^° or 93^° ). ClF₃ is T-shaped (angles about 87.5^° ).

Topic: VSEPR theory and shapes of molecules· Chemical Bonding and Molecular Structure

The species, having bond angles of 120° is :

1. \(ClF_3\)

2. \(NCl_3\)

3. \(BCl_3\)

4. \(PH_3\)

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Answer: 3. \(BCl_3\)

Key idea: \(120^\circ\) belongs to a trigonal planar molecule with no lone pair on the central atom.

\(\mathrm{BCl_3}\): B has 3 bond pairs, \(sp^2\), planar, \(120^\circ\). \(\mathrm{NCl_3}\) and \(\mathrm{PH_3}\) are pyramidal (one lone pair, angles near \(107^\circ\) or \(93^\circ\)). \(\mathrm{ClF_3}\) is T-shaped (angles about \(87.5^\circ\)).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The species, having bond angles of 120° is :

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