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Answer: 2. \(IBr_2^-, XeF_2\)

Key idea: isoelectronic means equal number of valence electrons, isostructural means same shape.

\(\mathrm{XeF_2}\): 8 + 14 = 22 valence electrons, linear (\(sp^3d\), 3 lone pairs). \(\mathrm{IBr_2^-}\): 7 + 14 + 1 = 22 electrons, 2 bond pairs and 3 lone pairs, linear. So the pair is isoelectronic and isostructural. \(\mathrm{TeI_2}\) is bent, \(\mathrm{IF_3}\) is T-shaped, and \(\mathrm{BeCl_2}\) has 16 electrons.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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