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Answer: 1. \(CH\equiv CH > CH_3-C\equiv CH > CH_2=CH_2 > CH_3-CH_3\)

Key idea: acidity of a C-H bond increases with the s-character of carbon.

Ethyne (sp, 50% s) > propyne (sp; methyl is electron-donating, so slightly less acidic) > ethene (\(sp^2\), 33% s) > ethane (\(sp^3\), 25% s).

Order: \(HC\equiv CH > CH_3C\equiv CH > CH_2=CH_2 > CH_3CH_3\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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