A carbon resistor of (47±4.7) kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be

1. Violet \(-\) Yellow \(-\) Orange \(-\) Silver

2. Yellow \(-\) Green \(-\) Violet \(-\) Gold

3. Yellow \(-\) Violet \(-\) Orange \(-\) Silver

4. Green \(-\) Orange \(-\) Violet \(-\) Gold

Doubtly Asked 30 Oct 2026 NEET UG 2018 neet Save WhatsApp Report

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Answer: 3. Yellow \(-\) Violet \(-\) Orange \(-\) Silver

Colour code digits: Yellow 4, Violet 7, Orange 3 (multiplier \(10^3\)), Silver \(\pm10\%\), Gold \(\pm5\%\).

\(47\ \mathrm{k\Omega}=47\times10^3\): Yellow, Violet, Orange. Tolerance \(4.7/47=10\%\) is Silver.

Sequence: Yellow - Violet - Orange - Silver (option 3).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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