1. J m K ⁻¹ 2. J m ⁻¹ K ⁻¹ 3. W m K ⁻¹ 4. W m ⁻¹ K ⁻¹

Answer: 4. W m ⁻¹ K ⁻¹ From Q/T=KA Δθ/L , K=(Q/t) L/A Δθ . Unit of Q/t is W, L is m, A is m ² , Δθ is K. So K has unit W m/m² K=W m⁻¹K⁻¹ .

Topic: Heat transfer: conduction, convection, radiation· Properties of Solids and Liquids

The unit of thermal conductivity is :

1. J m K\(^{-1}\)

2. J m\(^{-1}\) K\(^{-1}\)

3. W m K\(^{-1}\)

4. W m\(^{-1}\) K\(^{-1}\)

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Answer: 4. W m\(^{-1}\) K\(^{-1}\)

From \(\dfrac QT=\dfrac{KA\,\Delta\theta}{L}\), \(K=\dfrac{(Q/t)\,L}{A\,\Delta\theta}\).

Unit of \(Q/t\) is W, \(L\) is m, \(A\) is m\(^2\), \(\Delta\theta\) is K. So \(K\) has unit \(\dfrac{\text{W m}}{\text{m}^2\,\text{K}}=\text{W m}^{-1}\text{K}^{-1}\).

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The unit of thermal conductivity is :

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