1. PbF ₄ is covalent in nature 2. SiCl ₄ is easily hydrolysed 3. GeX ₄ (X = F, Cl, Br, I) is more stable than GeX ₂ 4. SnF ₄ is ionic in nature

Answer: 1. PbF ₄ is covalent in nature Go through the statements. PbF₄ is ionic (Pb(IV) with the very electronegative F), so the statement 'PbF4 is covalent' is incorrect. SiCl₄ is easily hydrolysed since Si has vacant d-orbitals: correct. For Ge, +4 is more stable than +2 (inert pair effect is weak in Ge): correct. SnF₄ is ionic: correct. The incorrect statement is option (1).

Topic: Electronic configuration and general trends, Group 13 and 14· p-Block Elements

Which of the following is incorrect statement ?

1. PbF\(_4\) is covalent in nature

2. SiCl\(_4\) is easily hydrolysed

3. GeX\(_4\) (X = F, Cl, Br, I) is more stable than GeX\(_2\)

4. SnF\(_4\) is ionic in nature

Doubtly Asked 30 Oct 2026 NEET UG 2019 Practice test neet Save WhatsApp Report

1 answer

Best answer

Answer: 1. PbF\(_4\) is covalent in nature

Go through the statements.

\(\mathrm{PbF_4}\) is ionic (Pb(IV) with the very electronegative F), so the statement 'PbF4 is covalent' is incorrect.
\(\mathrm{SiCl_4}\) is easily hydrolysed since Si has vacant d-orbitals: correct.
For Ge, +4 is more stable than +2 (inert pair effect is weak in Ge): correct.
\(\mathrm{SnF_4}\) is ionic: correct.

The incorrect statement is option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

Was this answer helpful?

Which of the following is incorrect statement ?

1 answer

Your answer