1. [M²][L⁻¹][T⁰] 2. [M][L⁻¹][T⁻¹] 3. [M][L⁰][T⁰] 4. [M²][L⁻²][T⁻¹]

Answer: 1. [M²][L⁻¹][T⁰] Key idea: get the dimensions of G from F=Gm₁m₂/r² . [G]=M⁻¹L³T⁻² and [E]=ML²T⁻² . E/G=dfracML²T⁻²M⁻¹L³T⁻²=M²L⁻¹T⁰ . Option 1.

Topic: Dimensions and dimensional analysis· Physics and Measurement

If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :

1. \([M^2][L^{-1}][T^0]\)

2. \([M][L^{-1}][T^{-1}]\)

3. \([M][L^0][T^0]\)

4. \([M^2][L^{-2}][T^{-1}]\)

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Answer: 1. \([M^2][L^{-1}][T^0]\)

Key idea: get the dimensions of G from \(F=Gm_1m_2/r^2\).

\([G]=M^{-1}L^{3}T^{-2}\) and \([E]=ML^2T^{-2}\).

\(\dfrac EG=\dfrac{ML^2T^{-2}}{M^{-1}L^3T^{-2}}=M^2L^{-1}T^0\). Option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :

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