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Answer: 4. magnetic permeability

Force has dimension \(MLT^{-2}\). Magnetic permeability appears in \(F=\dfrac{\mu_0}{4\pi}\dfrac{I_1I_2\,l}{d}\), so \(\mu_0\) has dimensions of force per current squared.

\([\mu_0]=\dfrac{MLT^{-2}}{A^2}=MLT^{-2}A^{-2}\).

Option (4) is correct.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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