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Topic: Dimensions and dimensional analysis· Physics and Measurement

Match List - I with List - II :List - I: (a) Gravitational constant (G) (b) Gravitational potential energy (c) Gravitational potential (d) Gravitational intensityList - II: (i) [L^2T^-2] (ii) [M^-1L^3T^-2] (iii) [LT^-2] (iv) [ML^2T^-2]Choose the corr…

Match List - I with List - II :

List - I: (a) Gravitational constant (G) (b) Gravitational potential energy (c) Gravitational potential (d) Gravitational intensity

List - II: (i) \([L^{2}T^{-2}]\) (ii) \([M^{-1}L^{3}T^{-2}]\) (iii) \([LT^{-2}]\) (iv) \([ML^{2}T^{-2}]\)

Choose the correct answer from the options given below :

1. (a) - (iv), (b) - (ii), (c) - (i), (d) - (iii)

2. (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)

3. (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

4. (a) - (ii), (b) - (iv), (c) - (iii), (d) - (i)

1 answer

Best answer

Answer: 3. (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

Find each dimension from its formula.

  • (a) \(G=\dfrac{Fr^2}{m^2}\): \([M^{-1}L^{3}T^{-2}]\), so (ii)
  • (b) Potential energy: \([ML^{2}T^{-2}]\), so (iv)
  • (c) Potential = energy per mass: \([L^{2}T^{-2}]\), so (i)
  • (d) Intensity = force per mass: \([LT^{-2}]\), so (iii)

This is option (3).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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