1. 41.5 kJ mol ⁻¹ 2. 83.0 kJ mol ⁻¹ 3. 166 kJ mol ⁻¹ 4. -83 kJ mol ⁻¹

Answer: 1. 41.5 kJ mol ⁻¹ Key idea: Arrhenius equation ln k=ln A-E_a/RT ; slope of ln k vs 1/T is -E_a/R . E_a=-slope× R=5×10³×8.314=41570\ J/mol≈41.5\ mathrmkJ mol⁻¹ .

Topic: Effect of temperature, Arrhenius equation, activation energy· Chemical Kinetics

The slope of Arrhenius Plot ( k v/s 1/T) of first order reaction is -5×10^3 K. The value of E_a of the reaction is. Choose the correct option for your answer.[Given R=8.314 J K^-1mol^-1]

1. 41.5 kJ mol\(^{-1}\)

2. 83.0 kJ mol\(^{-1}\)

3. 166 kJ mol\(^{-1}\)

4. \(-83\) kJ mol\(^{-1}\)

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Answer: 1. 41.5 kJ mol\(^{-1}\)

Key idea: Arrhenius equation \(\ln k=\ln A-\dfrac{E_a}{RT}\); slope of \(\ln k\) vs \(1/T\) is \(-E_a/R\).

\(E_a=-\text{slope}\times R=5\times10^3\times8.314=41570\ \mathrm{J/mol}\approx41.5\ \mathrm{kJ\,mol^{-1}}\).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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The slope of Arrhenius Plot ( k v/s 1/T) of first order reaction is -5×10^3 K. The value of E_a of the reaction is. Choose the correct option for your answer.[Given R=8.314 J K^-1mol^-1]

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