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Answer: 1. rate constant at two different temperatures.

Key idea: from the Arrhenius equation, \(\log\dfrac{k_2}{k_1}=\dfrac{E_a}{2.303R}\left(\dfrac{1}{T_1}-\dfrac{1}{T_2}\right)\).

Knowing \(k\) at two temperatures lets us solve for \(E_a\). A single rate constant, collision probability or orientation alone is not enough. Option 1.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report
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