1. √(3) IL 2. 3 IL 3. √(5) IL 4. 5 IL

Answer: 4. 5 IL Force on a wire: vec F=I vec L×vec B with vec L=Lhat i . hat i×(2hat i+3hat j-4hat k)=3hat k+4hat j (since hat i×hat j=hat k , hat i×hat k=-hat j ). |vec F|=IL√(3²+4²)=5IL . The answer is 5IL.

Topic: Force on current-carrying conductor, force between parallel currents· Magnetic Effects of Current and Magnetism

A wire carrying a current I along the positive x-axis has length L. It is kept in a magnetic field B=(2i+3j-4k) T. The magnitude of the magnetic force acting on the wire is :

1. \(\sqrt{3}\,IL\)

2. \(3\,IL\)

3. \(\sqrt{5}\,IL\)

4. \(5\,IL\)

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Answer: 4. \(5\,IL\)

Force on a wire: \(\vec F=I\,\vec L\times\vec B\) with \(\vec L=L\hat i\).

\(\hat i\times(2\hat i+3\hat j-4\hat k)=3\hat k+4\hat j\) (since \(\hat i\times\hat j=\hat k\), \(\hat i\times\hat k=-\hat j\)).

\(|\vec F|=IL\sqrt{3^2+4^2}=5IL\). The answer is 5IL.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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A wire carrying a current I along the positive x-axis has length L. It is kept in a magnetic field B=(2i+3j-4k) T. The magnitude of the magnetic force acting on the wire is :

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