Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate solution for 100 seconds is:(Given : Molar mass of Cu : 63 g mol^-1, 1F = 96487 C)

1. 0.0315 g

2. 3.15 g

3. 0.315 g

4. 31.5 g

Doubtly Asked 30 Oct 2026 NEET UG 2024 neet Save WhatsApp Report

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Answer: 3. 0.315 g

Key idea: \(Q=It\), then use Faraday's law for \(\mathrm{Cu^{2+}+2e^-\to Cu}\).

\(Q=9.6487\times100=964.87\) C, so moles of \(e^-\) = 964.87/96487 = 0.01.

Moles of Cu = 0.005; mass = \(0.005\times63=0.315\) g. Option 3.

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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