1. Hydrogen gas 2. Oxygen gas 3. H ₂ S gas 4. SO ₂ gas

Answer: 2. Oxygen gas In dilute H₂SO₄ with inert Pt electrodes, water is oxidised at the anode more easily than the sulphate ion. Anode: 2H₂O → O₂ + 4H^+ + 4e^- . Cathode: 2H^+ + 2e^- → H₂ . So the anode product is oxygen gas, option (2). (Concentrated H₂SO₄ would give peroxodisulphate.)

Topic: Electrolytic and galvanic cells, electrode potentials· Redox Reactions and Electrochemistry

On electrolysis of dil.sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be :

1. Hydrogen gas

2. Oxygen gas

3. H\(_2\)S gas

4. SO\(_2\) gas

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Answer: 2. Oxygen gas

In dilute \(\mathrm{H_2SO_4}\) with inert Pt electrodes, water is oxidised at the anode more easily than the sulphate ion.

Anode: \(\mathrm{2H_2O \rightarrow O_2 + 4H^+ + 4e^-}\). Cathode: \(\mathrm{2H^+ + 2e^- \rightarrow H_2}\).

So the anode product is oxygen gas, option (2). (Concentrated \(\mathrm{H_2SO_4}\) would give peroxodisulphate.)

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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On electrolysis of dil.sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be :

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