Answer: 1. 1 Electrode reaction: mathrmCa²⁺+2e^-→ Ca . One mole of Ca needs 2 F. Moles of Ca =20/40=0.5 mol. Charge =0.5×2=1 F. Answer: option (1).

The number of Faradays(F) required to produce 20 g of calcium from molten CaCl_2 (Atomic mass of Ca = 40 g mol^-1) is :

1. 1

2. 2

3. 3

4. 4

Doubtly Asked 30 Oct 2026 NEET UG 2020 neet Save WhatsApp Report

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Answer: 1. 1

Electrode reaction: \(\mathrm{Ca^{2+}+2e^-\rightarrow Ca}\). One mole of Ca needs 2 F.

Moles of Ca \(=20/40=0.5\) mol.

Charge \(=0.5\times2=1\) F.

Answer: option (1).

Doubtly AI · 30 Oct 2026 AI-generated · not yet verified Report

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