Solve the following equations by Cramer’s method i. 7x + 3y = 15; 12y - 5x = 39

Question

i. 7x + 3y = 15; 12y - 5x = 39

ii. $\frac{x+y-8}{2}=\frac{x+2y-14}{3}=\frac{3x-y}{4}$

Answer 1

Solving the folllowing equation with crammers method or rule

solution of 1

Given:

7x+3y=15  ....(1)

12y-5x=39 ........(2)

Equation (1) and (2) are in ax+by=c form 

comparing the equations with standard form 

a₁x+b₁y=c₁ and a₂x+b₂y=c₂

_{we get ,}

a1 = 7, b1 = 3, c1 = 15 and

a2 = -5, b2 = 12, c2 = 39