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Answer: 25 tickets of Rs 20 and 10 tickets of Rs 40 were sold.
Let the number of Rs 20 tickets be x and the number of Rs 40 tickets be y.
Total tickets: \(x + y = 35\) .....(1)
Total collection: \(20x + 40y = 900\)
Dividing by 20: \(x + 2y = 45\) .....(2)
Subtracting (1) from (2):
\((x + 2y) - (x + y) = 45 - 35\)
\(y = 10\)
Substituting \(y = 10\) in (1): \(x + 10 = 35\) ⇒ \(x = 25\)
Check: \(20 \times 25 + 40 \times 10 = 500 + 400 = 900\) ✓
Hence 25 tickets were sold at Rs 20 each and 10 tickets at Rs 40 each.
Answer: 25 tickets of Rs 20 and 10 tickets of Rs 40
Let \(x\) tickets of Rs 20 and \(y\) tickets of Rs 40 be sold.
Total tickets: \(x + y = 35\) ...(1)
Total collection: \(20x + 40y = 900\), i.e. \(x + 2y = 45\) ...(2)
Subtract (1) from (2): \(y = 10\). Then \(x = 35 - 10 = 25\).
Check: \(25 \times 20 + 10 \times 40 = 500 + 400 = \text{Rs } 900\).
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