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Answer: Speed on reaching the ground = 10 m/s; height of the table = 5 m.

Given: initial velocity \(u = 0\) (the ball just falls off), time \(t = 1\ \text{s}\), \(a = g = 10\ \text{m/s}^2\).

To find: final velocity \(v\) and height \(h\).

Speed on reaching the ground:

\(v = u + gt = 0 + 10 \times 1 = 10\ \text{m/s}\)

Height of the table:

\(h = ut + \tfrac{1}{2} g t^2 = 0 \times 1 + \tfrac{1}{2} \times 10 \times (1)^2 = 5\ \text{m}\)

The ball reaches the ground with a speed of 10 m/s and the table is 5 m high.

Doubtly · 4 May 2021 Report
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