Ionisation energy of He⁺ is 19.6×10⁻¹⁸J atom⁻¹. The energy of the first stationary state (n = 1) of Li²⁺ is (1)8.82×10⁻¹⁷ J atom⁻¹ (2) 4.41×10⁻¹⁶ J atom⁻¹ (3) -4.41×10⁻¹⁷ J atom⁻¹ (4) -2.2×10⁻¹⁵ J atom⁻¹

(3) -4.41×10⁻¹⁷ J atom^(-1 ) Given I.E = 19.6×10⁻¹⁸ I.E ∝ z² (I.E) Li²⁺/He⁺ = (9/4)×19.6×10⁻¹⁸ = -4.41×10⁻¹⁷

Ionisation energy of He+ is 19.6×10-18J atom-1. The energy of the first stationary state (n = 1) of Li2+ is

Ionisation energy of He⁺ is 19.6×10^-18J atom^-1. The energy of the first stationary state (n = 1) of Li²⁺ is

(1)8.82×10^-17 J atom^-1

(2) 4.41×10^-16 J atom^-1

(3) -4.41×10^-17 J atom^-1

(4) -2.2×10^-15 J atom^-1

Doubtly Asked 22 Jul 2022 Save WhatsApp Report

Best answer

(3) -4.41×10^-17 J atom^-1

Given I.E = 19.6×10^-18

I.E ∝ z²

(I.E) Li²⁺/He⁺ = (9/4)×19.6×10^-18

= -4.41×10^-17

Doubtly · 22 Jul 2022 Report

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