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Show that the force on each plate of a parallel plate capacitor has a magnitude equal to 12 QE, where Q is the charge on the capacitor, and E is the magnitude of the electric field between the plates. Explain the origin of the factor 12.

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Force = 12 QE
Work done = 12 V x Q
The physical origin of the factor 12 in the force formula lies in the fact that just outside the conductor, the field is E, and inside it is zero. So the average value E2 contributes to the force.

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