\({}^{290}_{82}X \xrightarrow{\alpha} Y \xrightarrow{e^+} Z \xrightarrow{\beta^-} P \xrightarrow{e^-} Q\)
In the nuclear emission stated above, the mass number and atomic number of the product \(Q\) respectively, are :
Every question from past board papers on Composition and size of nucleus, atomic masses, newest paper first. Open any question for its full worked answer.
\({}^{290}_{82}X \xrightarrow{\alpha} Y \xrightarrow{e^+} Z \xrightarrow{\beta^-} P \xrightarrow{e^-} Q\)
In the nuclear emission stated above, the mass number and atomic number of the product \(Q\) respectively, are :
The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to \(\left(\frac{1}{16}\right)^{th}\) of its initial value?
In the given nuclear reaction, the element X is :
\({}^{22}_{11}\text{Na} \rightarrow X + e^{+} + \nu\)
A nucleus of mass number 189 splits into two nuclei having mass number 125 and 64. The ratio of radius of two daughter nuclei respectively is :
A radioactive nucleus \(^A_ZX\) undergoes spontaneous decay in the sequence
\(^A_ZX \to {}_{Z-1}B \to {}_{Z-3}C \to {}_{Z-2}D\), where Z is the atomic number of element X. The possible decay particles in the sequence are :
The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be :
\(\alpha\)-particle consists of :
For a radioactive material, half-life is 10 minutes. If initially there are 600 number of nuclei, the time taken (in minutes) for the disintegration of 450 nuclei is
Radioactive material 'A' has decay constant '8\(\lambda\)' and material 'B' has decay constant '\(\lambda\)'. Initially they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that 'A' will be \(\frac{1}{e}\) ?
The half-life of a radioactive substance is 30 minutes. The time (in minutes) taken between 40% decay and 85% decay of the same radioactive substance is